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4+2(5x-5)=5-3(2x+1)
We move all terms to the left:
4+2(5x-5)-(5-3(2x+1))=0
We multiply parentheses
10x-(5-3(2x+1))-10+4=0
We calculate terms in parentheses: -(5-3(2x+1)), so:We add all the numbers together, and all the variables
5-3(2x+1)
determiningTheFunctionDomain -3(2x+1)+5
We multiply parentheses
-6x-3+5
We add all the numbers together, and all the variables
-6x+2
Back to the equation:
-(-6x+2)
10x-(-6x+2)-6=0
We get rid of parentheses
10x+6x-2-6=0
We add all the numbers together, and all the variables
16x-8=0
We move all terms containing x to the left, all other terms to the right
16x=8
x=8/16
x=1/2
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