2(3+2x)=20+7(x-1)

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Solution for 2(3+2x)=20+7(x-1) equation: 



2(3+2x)=20+7(x-1)

We move all terms to the left:

2(3+2x)-(20+7(x-1))=0

We add all the numbers together, and all the variables

2(2x+3)-(20+7(x-1))=0

We multiply parentheses

4x-(20+7(x-1))+6=0



We calculate terms in parentheses: -(20+7(x-1)), so:

20+7(x-1)

determiningTheFunctionDomain
7(x-1)+20

We multiply parentheses

7x-7+20

We add all the numbers together, and all the variables

7x+13

Back to the equation:

-(7x+13)



We get rid of parentheses

4x-7x-13+6=0

We add all the numbers together, and all the variables

-3x-7=0

We move all terms containing x to the left, all other terms to the right

-3x=7

x=7/-3

x=-2+1/3

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