20-(x+5)=4(x+1)+x

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Solution for 20-(x+5)=4(x+1)+x equation: 



20-(x+5)=4(x+1)+x

We move all terms to the left:

20-(x+5)-(4(x+1)+x)=0

We get rid of parentheses

-x-(4(x+1)+x)-5+20=0



We calculate terms in parentheses: -(4(x+1)+x), so:

4(x+1)+x

We add all the numbers together, and all the variables

x+4(x+1)

We multiply parentheses

x+4x+4

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We add all the numbers together, and all the variables

-1x-(5x+4)+15=0

We get rid of parentheses

-1x-5x-4+15=0

We add all the numbers together, and all the variables

-6x+11=0

We move all terms containing x to the left, all other terms to the right

-6x=-11

x=-11/-6

x=1+5/6

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