7(n-1)-1=2-5(n+1)

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Solution for 7(n-1)-1=2-5(n+1) equation: 



7(n-1)-1=2-5(n+1)

We move all terms to the left:

7(n-1)-1-(2-5(n+1))=0

We multiply parentheses

7n-(2-5(n+1))-7-1=0



We calculate terms in parentheses: -(2-5(n+1)), so:

2-5(n+1)

determiningTheFunctionDomain
-5(n+1)+2

We multiply parentheses

-5n-5+2

We add all the numbers together, and all the variables

-5n-3

Back to the equation:

-(-5n-3)



We add all the numbers together, and all the variables

7n-(-5n-3)-8=0

We get rid of parentheses

7n+5n+3-8=0

We add all the numbers together, and all the variables

12n-5=0

We move all terms containing n to the left, all other terms to the right

12n=5

n=5/12

n=5/12

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