2(2z-3)=3(z-4)

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Solution for 2(2z-3)=3(z-4) equation: 



2(2z-3)=3(z-4)

We move all terms to the left:

2(2z-3)-(3(z-4))=0

We multiply parentheses

4z-(3(z-4))-6=0



We calculate terms in parentheses: -(3(z-4)), so:

3(z-4)

We multiply parentheses

3z-12

Back to the equation:

-(3z-12)



We get rid of parentheses

4z-3z+12-6=0

We add all the numbers together, and all the variables

z+6=0

We move all terms containing z to the left, all other terms to the right

z=-6

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