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(3x+1/4x-2)=(3x+5/4x-7)
We move all terms to the left:
(3x+1/4x-2)-((3x+5/4x-7))=0
Domain of the equation: 4x-2)!=0
x∈R
Domain of the equation: 4x-7))!=0We get rid of parentheses
x∈R
3x+1/4x-((3x+5/4x-7))-2=0
We calculate fractions
3x+4x/16x^2+(-((3x+5*4x)/16x^2-2=0
We add all the numbers together, and all the variables
3x+4x/16x^2+(-((+3x+5*4x)/16x^2-2=0
We calculate fractions
We do not support expression: x^4
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