3r+1=7-(r+4)

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Solution for 3r+1=7-(r+4) equation: 



3r+1=7-(r+4)

We move all terms to the left:

3r+1-(7-(r+4))=0



We calculate terms in parentheses: -(7-(r+4)), so:

7-(r+4)

determiningTheFunctionDomain
-(r+4)+7

We get rid of parentheses

-r-4+7

We add all the numbers together, and all the variables

-1r+3

Back to the equation:

-(-1r+3)



We get rid of parentheses

3r+1r-3+1=0

We add all the numbers together, and all the variables

4r-2=0

We move all terms containing r to the left, all other terms to the right

4r=2

r=2/4

r=1/2

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