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3(x-4)=(x+10)
We move all terms to the left:
3(x-4)-((x+10))=0
We multiply parentheses
3x-((x+10))-12=0
We calculate terms in parentheses: -((x+10)), so:We get rid of parentheses
(x+10)
We get rid of parentheses
x+10
Back to the equation:
-(x+10)
3x-x-10-12=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11
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