2(2y-1)-6(1-2y)=2(4y-5)

Solution for 2(2y-1)-6(1-2y)=2(4y-5) equation:

2(2y-1)-6(1-2y)=2(4y-5)

We move all terms to the left:

2(2y-1)-6(1-2y)-(2(4y-5))=0

We add all the numbers together, and all the variables

2(2y-1)-6(-2y+1)-(2(4y-5))=0

We multiply parentheses

4y+12y-(2(4y-5))-2-6=0


We calculate terms in parentheses: -(2(4y-5)), so:

2(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)


We add all the numbers together, and all the variables

16y-(8y-10)-8=0

We get rid of parentheses

16y-8y+10-8=0

We add all the numbers together, and all the variables

8y+2=0

We move all terms containing y to the left, all other terms to the right

8y=-2

y=-2/8

y=-1/4