6(u+4)=-7(3u-3)+9u

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Solution for 6(u+4)=-7(3u-3)+9u equation: 



6(u+4)=-7(3u-3)+9u

We move all terms to the left:

6(u+4)-(-7(3u-3)+9u)=0

We multiply parentheses

6u-(-7(3u-3)+9u)+24=0



We calculate terms in parentheses: -(-7(3u-3)+9u), so:

-7(3u-3)+9u

We add all the numbers together, and all the variables

9u-7(3u-3)

We multiply parentheses

9u-21u+21

We add all the numbers together, and all the variables

-12u+21

Back to the equation:

-(-12u+21)



We get rid of parentheses

6u+12u-21+24=0

We add all the numbers together, and all the variables

18u+3=0

We move all terms containing u to the left, all other terms to the right

18u=-3

u=-3/18

u=-1/6

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