.(2y-1)-6.(1-2y)=2.(4y-5)

Solution for .(2y-1)-6.(1-2y)=2.(4y-5) equation:

.(2y-1)-6.(1-2y)=2.(4y-5)

We move all terms to the left:

.(2y-1)-6.(1-2y)-(2.(4y-5))=0

We add all the numbers together, and all the variables

.(2y-1)-6.(-2y+1)-(2.(4y-5))=0

We multiply parentheses

2y^2+12y-(2.(4y-5))-6+=0


We calculate terms in parentheses: -(2.(4y-5)), so:

2.(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)


We add all the numbers together, and all the variables

2y^2+12y-(8y-10)=0

We get rid of parentheses

2y^2+12y-8y+10=0

We add all the numbers together, and all the variables

2y^2+4y+10=0

a = 2; b = 4; c = +10;
Δ = b2-4ac
Δ = 42-4·2·10
Δ = -64
Delta is less than zero, so there is no solution for the equation