2(2x+2)+2(4x-1)=(4x-14)+(7x-14)+(6x+5)

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Solution for 2(2x+2)+2(4x-1)=(4x-14)+(7x-14)+(6x+5) equation: 



2(2x+2)+2(4x-1)=(4x-14)+(7x-14)+(6x+5)

We move all terms to the left:

2(2x+2)+2(4x-1)-((4x-14)+(7x-14)+(6x+5))=0

We multiply parentheses

4x+8x-((4x-14)+(7x-14)+(6x+5))+4-2=0



We calculate terms in parentheses: -((4x-14)+(7x-14)+(6x+5)), so:

(4x-14)+(7x-14)+(6x+5)

We get rid of parentheses

4x+7x+6x-14-14+5

We add all the numbers together, and all the variables

17x-23

Back to the equation:

-(17x-23)



We add all the numbers together, and all the variables

12x-(17x-23)+2=0

We get rid of parentheses

12x-17x+23+2=0

We add all the numbers together, and all the variables

-5x+25=0

We move all terms containing x to the left, all other terms to the right

-5x=-25

x=-25/-5

x=+5

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