-1/2(5n+3)=7/4(-n+3)

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Solution for -1/2(5n+3)=7/4(-n+3) equation: 



-1/2(5n+3)=7/4(-n+3)

We move all terms to the left:

-1/2(5n+3)-(7/4(-n+3))=0



Domain of the equation: 2(5n+3)!=0

n∈R





Domain of the equation: 4(-n+3))!=0

n∈R



We add all the numbers together, and all the variables

-1/2(5n+3)-(7/4(-1n+3))=0

We calculate fractions


(-4n(-)/(2(5n+3)*4(-1n+3)))+(-14n5/(2(5n+3)*4(-1n+3)))=0



We calculate terms in parentheses: +(-4n(-)/(2(5n+3)*4(-1n+3))), so:

-4n(-)/(2(5n+3)*4(-1n+3))

We add all the numbers together, and all the variables

-4n0/(2(5n+3)*4(-1n+3))

We multiply all the terms by the denominator


-4n0

We add all the numbers together, and all the variables

-4n

Back to the equation:

+(-4n)





We calculate terms in parentheses: +(-14n5/(2(5n+3)*4(-1n+3))), so:

-14n5/(2(5n+3)*4(-1n+3))

We multiply all the terms by the denominator


-14n5

We add all the numbers together, and all the variables

-14n^5

We do not support enpression: n^5

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