2n-4(n+3)=20

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Solution for 2n-4(n+3)=20 equation: 



2n-4(n+3)=20

We move all terms to the left:

2n-4(n+3)-(20)=0

We multiply parentheses

2n-4n-12-20=0

We add all the numbers together, and all the variables

-2n-32=0

We move all terms containing n to the left, all other terms to the right

-2n=32

n=32/-2

n=-16

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