2(2t+4)=5(t-3)

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Solution for 2(2t+4)=5(t-3) equation:



2(2t+4)=5(t-3)
We move all terms to the left:
2(2t+4)-(5(t-3))=0
We multiply parentheses
4t-(5(t-3))+8=0
We calculate terms in parentheses: -(5(t-3)), so:
5(t-3)
We multiply parentheses
5t-15
Back to the equation:
-(5t-15)
We get rid of parentheses
4t-5t+15+8=0
We add all the numbers together, and all the variables
-1t+23=0
We move all terms containing t to the left, all other terms to the right
-t=-23
t=-23/-1
t=+23

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