2-3(2+6z)=4(2+1)+18

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Solution for 2-3(2+6z)=4(2+1)+18 equation: 



2-3(2+6z)=4(2+1)+18

We move all terms to the left:

2-3(2+6z)-(4(2+1)+18)=0

We add all the numbers together, and all the variables

-3(6z+2)+2-(43+18)=0

We add all the numbers together, and all the variables

-3(6z+2)-59=0

We multiply parentheses

-18z-6-59=0

We add all the numbers together, and all the variables

-18z-65=0

We move all terms containing z to the left, all other terms to the right

-18z=65

z=65/-18

z=-3+11/18

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