2(4+3r)=3(r+3)+11

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Solution for 2(4+3r)=3(r+3)+11 equation: 



2(4+3r)=3(r+3)+11

We move all terms to the left:

2(4+3r)-(3(r+3)+11)=0

We add all the numbers together, and all the variables

2(3r+4)-(3(r+3)+11)=0

We multiply parentheses

6r-(3(r+3)+11)+8=0



We calculate terms in parentheses: -(3(r+3)+11), so:

3(r+3)+11

We multiply parentheses

3r+9+11

We add all the numbers together, and all the variables

3r+20

Back to the equation:

-(3r+20)



We get rid of parentheses

6r-3r-20+8=0

We add all the numbers together, and all the variables

3r-12=0

We move all terms containing r to the left, all other terms to the right

3r=12

r=12/3

r=4

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