2(2t+1)=32

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Solution for 2(2t+1)=32 equation:



2(2t+1)=32
We move all terms to the left:
2(2t+1)-(32)=0
We multiply parentheses
4t+2-32=0
We add all the numbers together, and all the variables
4t-30=0
We move all terms containing t to the left, all other terms to the right
4t=30
t=30/4
t=7+1/2

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