(2/3)(s-4)=-9

Solution for (2/3)(s-4)=-9 equation:

(2/3)(s-4)=-9

We move all terms to the left:

(2/3)(s-4)-(-9)=0


Domain of the equation: 3)(s-4)!=0

s∈R


We add all the numbers together, and all the variables

(+2/3)(s-4)-(-9)=0

We add all the numbers together, and all the variables

(+2/3)(s-4)+9=0

We multiply parentheses ..

(+2s^2+2/3*-4)+9=0

We multiply all the terms by the denominator


(+2s^2+2+9*3*-4)=0

We get rid of parentheses

2s^2+2-4+9*3*=0

We add all the numbers together, and all the variables

2s^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$s=\frac{-b}{2a}=\frac{0}{4}=0$