2(2s-4)+15=5(s-1)-(4s+1)

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Solution for 2(2s-4)+15=5(s-1)-(4s+1) equation: 



2(2s-4)+15=5(s-1)-(4s+1)

We move all terms to the left:

2(2s-4)+15-(5(s-1)-(4s+1))=0

We multiply parentheses

4s-(5(s-1)-(4s+1))-8+15=0



We calculate terms in parentheses: -(5(s-1)-(4s+1)), so:

5(s-1)-(4s+1)

We multiply parentheses

5s-(4s+1)-5

We get rid of parentheses

5s-4s-1-5

We add all the numbers together, and all the variables

s-6

Back to the equation:

-(s-6)



We add all the numbers together, and all the variables

4s-(s-6)+7=0

We get rid of parentheses

4s-s+6+7=0

We add all the numbers together, and all the variables

3s+13=0

We move all terms containing s to the left, all other terms to the right

3s=-13

s=-13/3

s=-4+1/3

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