(5-2i)=(3+3i)

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Solution for (5-2i)=(3+3i) equation: 



(5-2i)=(3+3i)

We move all terms to the left:

(5-2i)-((3+3i))=0

We add all the numbers together, and all the variables

(-2i+5)-((3i+3))=0

We get rid of parentheses

-2i-((3i+3))+5=0



We calculate terms in parentheses: -((3i+3)), so:

(3i+3)

We get rid of parentheses

3i+3

Back to the equation:

-(3i+3)



We get rid of parentheses

-2i-3i-3+5=0

We add all the numbers together, and all the variables

-5i+2=0

We move all terms containing i to the left, all other terms to the right

-5i=-2

i=-2/-5

i=2/5

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