P=-0.01x2+14x+1,200

Solution for P=-0.01x2+14x+1,200 equation:

=-0.01P^2+14P+1.200

We move all terms to the left:

-(-0.01P^2+14P+1.200)=0

We get rid of parentheses

0.01P^2-14P-1.200=0

We add all the numbers together, and all the variables

0.01P^2-14P-1.2=0

a = 0.01; b = -14; c = -1.2;
Δ = b2-4ac
Δ = -142-4·0.01·(-1.2)
Δ = 196.048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-\sqrt{196.048}}{2*0.01}=\frac{14-\sqrt{196.048}}{0.02}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+\sqrt{196.048}}{2*0.01}=\frac{14+\sqrt{196.048}}{0.02}
$