2(2n-1)/5=3(1-2n)/7

Solution for 2(2n-1)/5=3(1-2n)/7 equation:

2(2n-1)/5=3(1-2n)/7

We move all terms to the left:

2(2n-1)/5-(3(1-2n)/7)=0

We add all the numbers together, and all the variables

2(2n-1)/5-(3(-2n+1)/7)=0

We calculate fractions


4n/()+(-(3(-2n+1)*5)/()=0


We calculate terms in parentheses: +(-(3(-2n+1)*5)/(), so:

-(3(-2n+1)*5)/(

We multiply all the terms by the denominator


-(3(-2n+1)*5)


We calculate terms in parentheses: -(3(-2n+1)*5), so:

3(-2n+1)*5

We multiply parentheses

-30n+15

Back to the equation:

-(-30n+15)


We get rid of parentheses

30n-15

Back to the equation:

+(30n-15)


We get rid of parentheses

4n/()+30n-15=0

We multiply all the terms by the denominator


4n+30n*()-15*()=0

We add all the numbers together, and all the variables

4n+30n*()=0