2(2l+1)=6

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Solution for 2(2l+1)=6 equation: 



2(2l+1)=6

We move all terms to the left:

2(2l+1)-(6)=0

We multiply parentheses

4l+2-6=0

We add all the numbers together, and all the variables

4l-4=0

We move all terms containing l to the left, all other terms to the right

4l=4

l=4/4

l=1

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