2(3-2x)/8=6

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Solution for 2(3-2x)/8=6 equation: 



2(3-2x)/8=6

We move all terms to the left:

2(3-2x)/8-(6)=0

We add all the numbers together, and all the variables

2(-2x+3)/8-6=0

We multiply all the terms by the denominator


2(-2x+3)-6*8=0

We add all the numbers together, and all the variables

2(-2x+3)-48=0

We multiply parentheses

-4x+6-48=0

We add all the numbers together, and all the variables

-4x-42=0

We move all terms containing x to the left, all other terms to the right

-4x=42

x=42/-4

x=-10+1/2

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