4+(n-3)=8

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Solution for 4+(n-3)=8 equation: 



4+(n-3)=8

We move all terms to the left:

4+(n-3)-(8)=0

We add all the numbers together, and all the variables

(n-3)-4=0

We get rid of parentheses

n-3-4=0

We add all the numbers together, and all the variables

n-7=0

We move all terms containing n to the left, all other terms to the right

n=7

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