3(y-4)=2(2-y)

Solution for 3(y-4)=2(2-y) equation:

3(y-4)=2(2-y)

We move all terms to the left:

3(y-4)-(2(2-y))=0

We add all the numbers together, and all the variables

3(y-4)-(2(-1y+2))=0

We multiply parentheses

3y-(2(-1y+2))-12=0


We calculate terms in parentheses: -(2(-1y+2)), so:

2(-1y+2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)


We get rid of parentheses

3y+2y-4-12=0

We add all the numbers together, and all the variables

5y-16=0

We move all terms containing y to the left, all other terms to the right

5y=16

y=16/5

y=3+1/5