(4+5)+3=4+(c+3)

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Solution for (4+5)+3=4+(c+3) equation: 



(4+5)+3=4+(c+3)

We move all terms to the left:

(4+5)+3-(4+(c+3))=0

We add all the numbers together, and all the variables

-(4+(c+3))+3+9=0

We add all the numbers together, and all the variables

-(4+(c+3))+12=0



We calculate terms in parentheses: -(4+(c+3)), so:

4+(c+3)

determiningTheFunctionDomain
(c+3)+4

We get rid of parentheses

c+3+4

We add all the numbers together, and all the variables

c+7

Back to the equation:

-(c+7)



We get rid of parentheses

-c-7+12=0

We add all the numbers together, and all the variables

-1c+5=0

We move all terms containing c to the left, all other terms to the right

-c=-5

c=-5/-1

c=+5

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