2(2k-4)+3k=13

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Solution for 2(2k-4)+3k=13 equation: 



2(2k-4)+3k=13

We move all terms to the left:

2(2k-4)+3k-(13)=0

We add all the numbers together, and all the variables

3k+2(2k-4)-13=0

We multiply parentheses

3k+4k-8-13=0

We add all the numbers together, and all the variables

7k-21=0

We move all terms containing k to the left, all other terms to the right

7k=21

k=21/7

k=3

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