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x-3=(2x+3)/5
We move all terms to the left:
x-3-((2x+3)/5)=0
We multiply all the terms by the denominator
x*5)-((2x+3)-3*5)=0
We add all the numbers together, and all the variables
x*5)-((2x+3)=0
Wy multiply elements
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{10}=0$
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