1/2(8a-20)=2(a+16)

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Solution for 1/2(8a-20)=2(a+16) equation: 



1/2(8a-20)=2(a+16)

We move all terms to the left:

1/2(8a-20)-(2(a+16))=0



Domain of the equation: 2(8a-20)!=0

a∈R



We multiply all the terms by the denominator


-((2(a+16)))*2(8a-20)+1=0



We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))*2(8a-20), so:

(2(a+16)))*2(8a-20





We calculate terms in parentheses: -((2(a+16)))

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