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3(x-4)=5(x-4)
We move all terms to the left:
3(x-4)-(5(x-4))=0
We multiply parentheses
3x-(5(x-4))-12=0
We calculate terms in parentheses: -(5(x-4)), so:We get rid of parentheses
5(x-4)
We multiply parentheses
5x-20
Back to the equation:
-(5x-20)
3x-5x+20-12=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4
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