2(2k-1)=4)k-2)

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Solution for 2(2k-1)=4)k-2) equation: 



2(2k-1)=4)k-2)

We move all terms to the left:

2(2k-1)-(4)k-2))=0

We add all the numbers together, and all the variables

-4k+2(2k-1)=0

We multiply parentheses

-4k+4k-2=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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