-4+(2c-5)=15

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Solution for -4+(2c-5)=15 equation: 



-4+(2c-5)=15

We move all terms to the left:

-4+(2c-5)-(15)=0

We add all the numbers together, and all the variables

(2c-5)-19=0

We get rid of parentheses

2c-5-19=0

We add all the numbers together, and all the variables

2c-24=0

We move all terms containing c to the left, all other terms to the right

2c=24

c=24/2

c=12

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