8x-2(3x-6)+4=2(x+4)+8

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Solution for 8x-2(3x-6)+4=2(x+4)+8 equation: 



8x-2(3x-6)+4=2(x+4)+8

We move all terms to the left:

8x-2(3x-6)+4-(2(x+4)+8)=0

We multiply parentheses

8x-6x-(2(x+4)+8)+12+4=0



We calculate terms in parentheses: -(2(x+4)+8), so:

2(x+4)+8

We multiply parentheses

2x+8+8

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

2x-(2x+16)+16=0

We get rid of parentheses

2x-2x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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