2(12-y)-23=(2y-1)

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Solution for 2(12-y)-23=(2y-1) equation:



2(12-y)-23=(2y-1)
We move all terms to the left:
2(12-y)-23-((2y-1))=0
We add all the numbers together, and all the variables
2(-1y+12)-((2y-1))-23=0
We multiply parentheses
-2y-((2y-1))+24-23=0
We calculate terms in parentheses: -((2y-1)), so:
(2y-1)
We get rid of parentheses
2y-1
Back to the equation:
-(2y-1)
We add all the numbers together, and all the variables
-2y-(2y-1)+1=0
We get rid of parentheses
-2y-2y+1+1=0
We add all the numbers together, and all the variables
-4y+2=0
We move all terms containing y to the left, all other terms to the right
-4y=-2
y=-2/-4
y=1/2

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