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2(2a+3)=3(a+5)
We move all terms to the left:
2(2a+3)-(3(a+5))=0
We multiply parentheses
4a-(3(a+5))+6=0
We calculate terms in parentheses: -(3(a+5)), so:We get rid of parentheses
3(a+5)
We multiply parentheses
3a+15
Back to the equation:
-(3a+15)
4a-3a-15+6=0
We add all the numbers together, and all the variables
a-9=0
We move all terms containing a to the left, all other terms to the right
a=9
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