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3(5a-4)=2(2a+4)
We move all terms to the left:
3(5a-4)-(2(2a+4))=0
We multiply parentheses
15a-(2(2a+4))-12=0
We calculate terms in parentheses: -(2(2a+4)), so:We get rid of parentheses
2(2a+4)
We multiply parentheses
4a+8
Back to the equation:
-(4a+8)
15a-4a-8-12=0
We add all the numbers together, and all the variables
11a-20=0
We move all terms containing a to the left, all other terms to the right
11a=20
a=20/11
a=1+9/11
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