17x+3(x-4)=2(12+x)

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Solution for 17x+3(x-4)=2(12+x) equation: 



17x+3(x-4)=2(12+x)

We move all terms to the left:

17x+3(x-4)-(2(12+x))=0

We add all the numbers together, and all the variables

17x+3(x-4)-(2(x+12))=0

We multiply parentheses

17x+3x-(2(x+12))-12=0



We calculate terms in parentheses: -(2(x+12)), so:

2(x+12)

We multiply parentheses

2x+24

Back to the equation:

-(2x+24)



We add all the numbers together, and all the variables

20x-(2x+24)-12=0

We get rid of parentheses

20x-2x-24-12=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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