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2(1/4x+2)=3(2/5x)-3
We move all terms to the left:
2(1/4x+2)-(3(2/5x)-3)=0
Domain of the equation: 4x+2)!=0
x∈R
Domain of the equation: 5x)-3)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(1/4x+2)-(3(+2/5x)-3)=0
We multiply parentheses
2x-(3(+2/5x)-3)+4=0
We multiply all the terms by the denominator
2x*5x)-3)-(3(+4*5x)-3)+2=0
Wy multiply elements
10x^2+20x=0
a = 10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·10·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*10}=\frac{-40}{20} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*10}=\frac{0}{20} =0 $
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