(3x+18)+(9x-27)=99

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Solution for (3x+18)+(9x-27)=99 equation: 



(3x+18)+(9x-27)=99

We move all terms to the left:

(3x+18)+(9x-27)-(99)=0

We get rid of parentheses

3x+9x+18-27-99=0

We add all the numbers together, and all the variables

12x-108=0

We move all terms containing x to the left, all other terms to the right

12x=108

x=108/12

x=9

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