If it's not what You are looking for type in the equation solver your own equation and let us solve it.
p-3/5(10p-5)=7
We move all terms to the left:
p-3/5(10p-5)-(7)=0
Domain of the equation: 5(10p-5)!=0We multiply all the terms by the denominator
p∈R
p*5(10p-5)-7*5(10p-5)-3=0
Wy multiply elements
5p^2(1-35p(1-3=0
| −9x2+x+3=0 | | 3/4=1/2y | | (3x+18)+(9x-27)=99 | | 0=x^2-24x+80 | | 3/5x+2=2/3x-1 | | 5(x+3)—(5x+15)=0 | | 0.0004/x=0.01 | | 2x2−16x+14=0 | | 1/7(150+r)=20 | | (6)(8x)=(16)(3) | | X+8=7x-6 | | 3(x-1.8)=2x+ | | 5x+8+7x=-28 | | (x+7)^2+1=12 | | x+5/7=8/3 | | 1234=1234x+x | | 7(x-19)=35 | | x+5/3=8/3 | | 5x+8+7x=28 | | 1/16(6)x=81 | | 77=m-17 | | 8(2x+8)=128 | | y+135+190=180 | | V^2-12v-55=0 | | 6w+1=-1 | | x+45+135=180 | | 2/5(2x-15)=2 | | g(4)=25−3⋅4 | | 2x=5=11 | | 3y^2=13-10=0 | | 25(2x−15)=2 | | (x+2)8=48 |