2(1/2x+1)=3(2x-1)+4(2x+1)

Solution for 2(1/2x+1)=3(2x-1)+4(2x+1) equation:

2(1/2x+1)=3(2x-1)+4(2x+1)

We move all terms to the left:

2(1/2x+1)-(3(2x-1)+4(2x+1))=0


Domain of the equation: 2x+1)!=0

x∈R


We multiply parentheses

2x-(3(2x-1)+4(2x+1))+2=0


We calculate terms in parentheses: -(3(2x-1)+4(2x+1)), so:

3(2x-1)+4(2x+1)

We multiply parentheses

6x+8x-3+4

We add all the numbers together, and all the variables

14x+1

Back to the equation:

-(14x+1)


We get rid of parentheses

2x-14x-1+2=0

We add all the numbers together, and all the variables

-12x+1=0

We move all terms containing x to the left, all other terms to the right

-12x=-1

x=-1/-12

x=1/12