2(3x-2)=10-x

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Solution for 2(3x-2)=10-x equation: 



2(3x-2)=10-x

We move all terms to the left:

2(3x-2)-(10-x)=0

We add all the numbers together, and all the variables

2(3x-2)-(-1x+10)=0

We multiply parentheses

6x-(-1x+10)-4=0

We get rid of parentheses

6x+1x-10-4=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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