1/8t+1/6t=7

Solution for 1/8t+1/6t=7 equation:

1/8t+1/6t=7

We move all terms to the left:

1/8t+1/6t-(7)=0


Domain of the equation: 8t!=0

t!=0/8

t!=0

t∈R



Domain of the equation: 6t!=0

t!=0/6

t!=0

t∈R


We calculate fractions


6t/48t^2+8t/48t^2-7=0

We multiply all the terms by the denominator


6t+8t-7*48t^2=0

We add all the numbers together, and all the variables

14t-7*48t^2=0

Wy multiply elements

-336t^2+14t=0

a = -336; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-336)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-336}=\frac{-28}{-672}
=1/24
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-336}=\frac{0}{-672}
=0
$