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1x+2x/3x=100
We move all terms to the left:
1x+2x/3x-(100)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+2x/3x-100=0
We multiply all the terms by the denominator
x*3x+2x-100*3x=0
We add all the numbers together, and all the variables
2x+x*3x-100*3x=0
Wy multiply elements
3x^2+2x-300x=0
We add all the numbers together, and all the variables
3x^2-298x=0
a = 3; b = -298; c = 0;
Δ = b2-4ac
Δ = -2982-4·3·0
Δ = 88804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{88804}=298$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-298)-298}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-298)+298}{2*3}=\frac{596}{6} =99+1/3 $
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