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5/4x-9/5=3/8x
We move all terms to the left:
5/4x-9/5-(3/8x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/4x-(+3/8x)-9/5=0
We get rid of parentheses
5/4x-3/8x-9/5=0
We calculate fractions
(-2304x^2)/800x^2+1000x/800x^2+(-300x)/800x^2=0
We multiply all the terms by the denominator
(-2304x^2)+1000x+(-300x)=0
We get rid of parentheses
-2304x^2+1000x-300x=0
We add all the numbers together, and all the variables
-2304x^2+700x=0
a = -2304; b = 700; c = 0;
Δ = b2-4ac
Δ = 7002-4·(-2304)·0
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{490000}=700$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(700)-700}{2*-2304}=\frac{-1400}{-4608} =175/576 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(700)+700}{2*-2304}=\frac{0}{-4608} =0 $
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