3x+4(x+2)=64

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Solution for 3x+4(x+2)=64 equation: 



3x+4(x+2)=64

We move all terms to the left:

3x+4(x+2)-(64)=0

We multiply parentheses

3x+4x+8-64=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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