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1/2x+1/5=-5(2/3x-3)
We move all terms to the left:
1/2x+1/5-(-5(2/3x-3))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x-3))!=0We calculate fractions
x∈R
(-(-5(2*2x*5)/6x^2+18x^2/6x^2+3x/6x^2=0
We can not solve this equation
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