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x2+24x-25=0
We add all the numbers together, and all the variables
x^2+24x-25=0
a = 1; b = 24; c = -25;
Δ = b2-4ac
Δ = 242-4·1·(-25)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*1}=\frac{2}{2} =1 $
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